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X^2-9.5X+16=0
a = 1; b = -9.5; c = +16;
Δ = b2-4ac
Δ = -9.52-4·1·16
Δ = 26.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{26.25}}{2*1}=\frac{9.5-\sqrt{26.25}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{26.25}}{2*1}=\frac{9.5+\sqrt{26.25}}{2} $
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